Midvalley Estates (in Salt Lake County, UT) Populated Place Profile

Midvale Local Links & Resources:
Hotels | Resources | ALL Midvale Content

Midvalley Estates (GNIS FID: 1452595) is a populated place LOCATED WITHIN the City of Midvale. In turn, the City of Midvale is located within Salt Lake County.

Midvalley Estates is located at latitude 40.613 and longitude -111.87. The elevation of Midvalley Estates is 4,468 feet above mean sea level.

Since Midvalley Estates is located within the City of Midvale, all of the census and demographic data for residents of Midvalley Estates are included as part of the information reported for City of Midvale in the "Data" tab above.

In similar fashion, ALL OF THE NAVIGATION TABS ABOVE ARE FOR THE City of Midvale Community Profile.

Salt Lake County: Cities & Towns | ZIP Codes | Features (airports, churches, hospitals, etc.)

Neighborhood Data

Address Based Hyperlocal Data Input an address and get data & demographics for the pertinent census block group (CBG), a searchable map and a customized directory. The CBG is the smallest geographical unit used by the Census Bureau for reporting certain data.


Search the map for:

BIG Map | Driving Directions | Data Source - USGS GNIS FID: 1452595

BOUNDARY MAPS: City of Midvale | Salt Lake City Division | Salt Lake County


Nearby Cities, Towns & Census Designated Places

Midvale, UT (1.4 miles W)
Cottonwood Heights, UT (3.1 miles E)
Sandy city, UT (3.1 miles SSE)
White City, UT (3.4 miles S)
West Jordan, UT (3.6 miles W)
Murray, UT (3.9 miles NNW)
Granite, UT (4.3 miles SE)
Holladay, UT (4.5 miles NNE)
South Jordan, UT (4.7 miles SW)
Millcreek, UT (5.1 miles N)

Nearby Neighborhoods, Subdivisions & Other Small Populated Places

Wilshire Park, UT (< 0.1 mile)
Marion Village, UT (< 0.1 mile)
Ponderosa Park, UT (< 0.1 mile)
Silver Acres, UT (< 0.1 mile)
Cedar Terrace, UT (< 0.1 mile)
Daysen Heights, UT (< 0.1 mile)
Granduer Chalet, UT (< 0.1 mile)
Huish, UT (< 0.1 mile)
Country Squire Acres, UT (< 0.1 mile)
Eaglebrook Estates, UT (< 0.1 mile)